Peanuts by Charles Schulz for May 07, 1974

  1. America
    gamer2k4  over 11 years ago

    The answer is five, right?

    SSSSMMMSSSMMMSSSMMMSSSMMMSSSMMMSSSS

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  2. Missing large
    empireatwar  over 7 years ago

    Why is she saying, “Defense! Defense!”?

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  3. Capture
    All...  over 4 years ago

    This one is pretty easy (assuming the question sees all of one type of book as being the exact same book and not, for instance, different volumes). Because all the math books have to be together, they can be treated as a single unit, which leaves you with only 5 positions (4 science books + 1 set of math books), and, because only one of the objects in those positions is unique, that means there are exactly 5 permutations/arrangements.

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  4. Photo
    Stormwyrm  over 3 years ago

    There are three math books, so there are 3! = 6 ways of arranging them. There are four science books, so there are 4! = 24 ways of arranging them. For each way of arranging the science books there are three ways of putting the math books between them, and it is also possible to put the math books before them and after them, so there are five total ways. Thus the number of ways to arrange the books so that the math books are always together is 24 × 5 × 6 = 720.

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  5. Screenshot 20220315 023952 edge
    thatdarnfurry  over 2 years ago

    I only got 1 way. Group the maths books together then put the science ones next to them

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